문제
Farmer John has a boolean statement that is keywords long (, odd). Only or appear in odd positions, while only and appear in even positions.
A phrase of the form , where and are either or , and is or , evaluates as follows:
: This evaluates to true if both and are true, and false otherwise.: This evaluates to true if either or is true, and false otherwise.
When evaluating the statement, FJ has to take the order of precedence in Moo Language into account. Similar to C++, takes priority over . More specifically, to evaluate the statement, repeat the following step until the statement consists of only one keyword.
If the statement contains an , choose any of them and replace the phrase surrounding it with its evaluation.Otherwise, the statement contains an . Choose any of them and replace the phrase surrounding it with its evaluation.
It may be proven that if multiple phrases can be evaluated during a given step, it does not matter which one is chosen; the statement will always evaluate to the same value.
FJ has queries. In each query, he gives you two integers and (, and are both odd), and deletes the segment from keyword to keyword inclusive. In turn, he wishes to replace the segment he just deleted with just one simple or so that the whole statement evaluates to a certain boolean value. Help FJ determine if it's possible!
입력
The first line contains and .
The next line contains strings, a valid boolean statement.
The following lines contain two integers and , and a string or , denoting whether he wants the whole statement to evaluate to true or false.
출력
Output a string of length , where the 'th character is Y if the 'th query is possible, otherwise N.
예제 입력 1
5 7
false and true or true
1 1 false
1 3 true
1 5 false
3 3 true
3 3 false
5 5 false
5 5 true
예제 출력 1
NYYYNYY
예제 입력 2
13 4
false or true and false and false and true or true and false
1 5 false
3 11 true
3 11 false
13 13 true
예제 출력 2
YNYY
점수
Inputs 3-5: Inputs 6-8: Inputs 9-26: No additional constraints.
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